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asked Apr 18, 2014 in Education & Reference by Yogi (180 points) | 46 views
    

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<?php
$firstdate               = "2019-06-01";
$seconddate        = "2014-06-22";
 
$differnce              = abs(strtotime($seconddate) - strtotime($firstdate));
 
$years                   =   floor($differnce / (365*60*60*24));
$months               =   floor(($differnce - $years * 365*60*60*24) / (30*60*60*24));
$days                    =   floor(($differnce- $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
 
printf("%d years, %d months, %d days", $years, $months, $days);
?>
answered Apr 18, 2014 by Sam (1,380 points)

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